fierke/galtonbrett
3
3
Fork 0
Code Issues 2 Pull Requests Activity

Compare commits

base: fierke/galtonbrett:51a7fa5eb28ad5f65db8dca529428e61e10cd5b1
Branches Tags
fierke/galtonbrett:main fierke/galtonbrett:stirling-integration fierke/galtonbrett:galton-subsection
..
compare: fierke/galtonbrett:main
Branches Tags
fierke/galtonbrett:main fierke/galtonbrett:stirling-integration fierke/galtonbrett:galton-subsection
4 Commits
51a7fa5eb2 .. main
Author SHA1 Message Date
fierke 6f9a744599 fix: anordnung binomialkoeffizienten war auch in der Lösung falsch, aber lugga ist es beim Überarbeiten nicht aufgefallen 2026-07-24 09:21:00 +02:00
fierke e0bbcda26c fix: merge doesnt work with compiled files... 2026-07-23 17:10:47 +02:00
fierke e9a6362398 Merge branch 'main' of https://git.mypapercloud.de/fierke/galtonbrett 2026-07-23 17:09:47 +02:00
fierke dd7fa8643f fix: binomialkoeffizienten falsch zugeordnet, warum auch immer 2026-07-23 17:07:04 +02:00
5 changed files with 20 additions and 39 deletions
Expand all files Collapse all files
galton.pdf
BIN
View File
Binary file not shown.
material/ab1.pdf
BIN
View File
Binary file not shown.
material/ab1.tex
+4 -4
View File
@@ -344,22 +344,22 @@
\node at (12.25,14.1875) {$\binom{1}{1}=$};
\draw (10.25,13.5) rectangle (13,12.125);
\node at (10.875,12.8125) {$\binom{2}{0}=$};
\node at (10.875,12.8125) {$\binom{2}{1}=$};
\draw (7.5,13.5) rectangle (10.25,12.125);
\node at (8.125,12.8125) {$\binom{2}{1}=$};
\node at (8.125,12.8125) {$\binom{2}{0}=$};
\draw (13,13.5) rectangle (15.75,12.125);
\node at (13.625,12.8125) {$\binom{2}{2}=$};
\draw (11.625,12.125) rectangle (14.375,10.75);
\node at (12.25,11.4375) {$\binom{3}{0}=$};
\node at (12.25,11.4375) {$\binom{3}{2}=$};
\draw (8.875,12.125) rectangle (11.625,10.75);
\node at (9.5,11.4375) {$\binom{3}{1}=$};
\draw (6.125,12.125) rectangle (8.875,10.75);
\node at (6.75,11.4375) {$\binom{3}{2}=$};
\node at (6.75,11.4375) {$\binom{3}{0}=$};
\draw (14.375,12.125) rectangle (17.125,10.75);
\node at (15,11.4375) {$\binom{3}{3}=$};
material/ab1_Lös.pdf
BIN
View File
Binary file not shown.
material/ab1_Lös.tex
+13 -32
View File
@@ -234,32 +234,13 @@
\ifoot{\normalfont\normalsize Fierke, Janik, Weidlich}
\section{\curtitle}
\begin{figure}[H]
\centering
% Erstes Bild
\begin{minipage}[t]{0.7\textwidth}
\centering
Im Stochastik Unterricht ist dir sicherlich schon einmal die
Formel des Binomialkoeffizienten (Abb. \ref{fig:bino}) begegnet.
Im Stochastikunterricht ist dir sicherlich schoneinmal die Formel des Binomialkoeffienten begegnet:
\begin{definitionbox}[Binomialkoeffizient]
Der Binomialkoeffizient gibt die Anzahl der Möglichkeiten an, aus einer Menge mit $n$ Elementen $k$ verschiedene Elemente auszuwählen.
\end{definitionbox}
\end{minipage}
\hfill
% Zweites Bild
\begin{minipage}[t]{0.25\textwidth}
\centering
Der Binomialkoeffizient gibt die Anzahl der Möglichkeiten an, aus einer Menge mit $n$ Elementen $k$ verschiedene Elemente auszuwählen:
\[
\binom{n}{k}=\frac{n!}{k!(n-k)!}
\]
\caption{Formel Binomialkoeffizienten}
\label{fig:bino}
\end{minipage}
\end{figure}
Im Stochastikunterricht ist dir sicherlich schoneinmal die Formel des Binomialkoeffienten begegnet:
\end{definitionbox}
Zum Warmwerden berechnen wir:
@@ -354,34 +335,34 @@
\begin{circuitikz}[x=0.8cm,y=0.8cm]
\draw (10.25,16.25) rectangle (13,14.875);
\node at (10.875,15.5625) {$\binom{0}{0}=1$};
\node at (11.75,15.5625) {$\binom{0}{0}=1$};
\draw (8.875,14.875) rectangle (11.625,13.5);
\node at (9.5,14.1875) {$\binom{1}{0}=1$};
\node at (10.25,14.1875) {$\binom{1}{0}=1$};
\draw (11.625,14.875) rectangle (14.375,13.5);
\node at (12.25,14.1875) {$\binom{1}{1}=1$};
\node at (13,14.1875) {$\binom{1}{1}=1$};
\draw (10.25,13.5) rectangle (13,12.125);
\node at (10.875,12.8125) {$\binom{2}{0}=1$};
\node at (11.75,12.8125) {$\binom{2}{1}=2$};
\draw (7.5,13.5) rectangle (10.25,12.125);
\node at (8.125,12.8125) {$\binom{2}{1}=2$};
\node at (8.875,12.8125) {$\binom{2}{0}=1$};
\draw (13,13.5) rectangle (15.75,12.125);
\node at (13.625,12.8125) {$\binom{2}{2}=1$};
\node at (14.375,12.8125) {$\binom{2}{2}=1$};
\draw (11.625,12.125) rectangle (14.375,10.75);
\node at (12.25,11.4375) {$\binom{3}{0}=1$};
\node at (13,11.4375) {$\binom{3}{2}=3$};
\draw (8.875,12.125) rectangle (11.625,10.75);
\node at (9.5,11.4375) {$\binom{3}{1}=3$};
\node at (10.25,11.4375) {$\binom{3}{1}=3$};
\draw (6.125,12.125) rectangle (8.875,10.75);
\node at (6.75,11.4375) {$\binom{3}{2}=3$};
\node at (7.5,11.4375) {$\binom{3}{0}=1$};
\draw (14.375,12.125) rectangle (17.125,10.75);
\node at (15,11.4375) {$\binom{3}{3}=1$};
\node at (15.75,11.4375) {$\binom{3}{3}=1$};
\end{circuitikz}
\end{figure}
\end{enumerate}