ab: seite 1 fertig (hat länger gedauert weil tikz)
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@@ -104,11 +104,11 @@
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after skip=10pt
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}
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\newtcolorbox{taskbox}[1][]{
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\newtcolorbox{extrataskbox}[1][]{
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before title={\refstepcounter{commoncounter}}, % KRITISCH: vor dem Titel!
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title={Aufgabe \thecommoncounter: #1},
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title={Zusatzaufgabe: #1},
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colback=white,
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colframe=white!75!orange,
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colframe=white!75!red,
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fonttitle=\bfseries,
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boxrule=0.6mm,
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coltitle=black,
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@@ -242,12 +242,102 @@
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\begin{center}
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\textit{Die Summe des Steins ist die Summe der darüberliegenden Steine. }
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\end{center}
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\begin{figure}[H]
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\begin{figure}[!ht]
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\centering
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\includegraphics[width=0.7\linewidth]{pyramide_01}
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\begin{circuitikz}[x=0.8cm,y=0.8cm]
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% oberste Reihe
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\draw[dashed,gray!60] (8.875,16.25) rectangle (10.25,14.875);
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\node[text=gray!60] at (9.55,15.5625) {0};
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\draw (10.25,16.25) rectangle (13,14.875);
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\node[anchor=center] at (11.6,15.5625) {1};
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\draw[dashed,gray!60] (13,16.25) rectangle (14.375,14.875);
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\node[text=gray!60] at (13.75,15.5625) {0};
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% zweite Reihe
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\draw[dashed,gray!60] (7.5,14.875) rectangle (8.875,13.5);
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\node[text=gray!60] at (8.175,14.1875) {0};
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\draw (8.875,14.875) rectangle (11.625,13.5);
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\draw (11.625,14.875) rectangle (14.375,13.5);
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\draw[dashed,gray!60] (14.375,14.875) rectangle (15.75,13.5);
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\node[text=gray!60] at (15,14.1875) {0};
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% dritte Reihe
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\draw[dashed,gray!60] (6.125,13.5) rectangle (7.5,12.125);
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\node[text=gray!60] at (6.8,12.8125) {0};
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\draw (7.5,13.5) rectangle (10.25,12.125);
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\draw (10.25,13.5) rectangle (13,12.125);
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\draw (13,13.5) rectangle (15.75,12.125);
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\draw[dashed,gray!60] (15.75,13.5) rectangle (17.125,12.125);
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\node[text=gray!60] at (16.375,12.8125) {0};
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% unterste Reihe
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\draw[dashed,gray!60] (4.75,12.125) rectangle (6.125,10.75);
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\node[text=gray!60] at (5.425,11.4375) {0};
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\draw (6.125,12.125) rectangle (8.875,10.75);
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\draw (8.875,12.125) rectangle (11.625,10.75);
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\draw (11.625,12.125) rectangle (14.375,10.75);
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\draw (14.375,12.125) rectangle (17.125,10.75);
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\draw[dashed,gray!60] (17.125,12.125) rectangle (18.5,10.75);
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\node[text=gray!60] at (17.875,11.4375) {0};
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\end{circuitikz}
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\end{figure}
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\item Berechne die Steine der Pyramide:
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\begin{figure}[!ht]
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\centering
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\begin{circuitikz}[x=0.8cm,y=0.8cm]
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\draw (10.25,16.25) rectangle (13,14.875);
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\node at (10.875,15.5625) {$\binom{0}{0}=$};
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\draw (8.875,14.875) rectangle (11.625,13.5);
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\node at (9.5,14.1875) {$\binom{1}{0}=$};
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\draw (11.625,14.875) rectangle (14.375,13.5);
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\node at (12.25,14.1875) {$\binom{1}{1}=$};
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\draw (10.25,13.5) rectangle (13,12.125);
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\node at (10.875,12.8125) {$\binom{2}{0}=$};
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\draw (7.5,13.5) rectangle (10.25,12.125);
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\node at (8.125,12.8125) {$\binom{2}{1}=$};
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\draw (13,13.5) rectangle (15.75,12.125);
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\node at (13.625,12.8125) {$\binom{2}{2}=$};
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\draw (11.625,12.125) rectangle (14.375,10.75);
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\node at (12.25,11.4375) {$\binom{3}{0}=$};
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\draw (8.875,12.125) rectangle (11.625,10.75);
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\node at (9.5,11.4375) {$\binom{3}{1}=$};
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\draw (6.125,12.125) rectangle (8.875,10.75);
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\node at (6.75,11.4375) {$\binom{3}{2}=$};
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\draw (14.375,12.125) rectangle (17.125,10.75);
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\node at (15,11.4375) {$\binom{3}{3}=$};
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\end{circuitikz}
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\end{figure}
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\end{enumerate}
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\begin{extrataskbox}
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Entwirf einen Computeralgorithmus, der den Binomialkoeffizienten berechnet, ohne dass dieser die Fakultät benutzt!
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\end{extrataskbox}
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\label{LastPage}
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\end{document}
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